Home KINEMATICS LAWS OF MOTION Previous year Questions A ball is moving with a velocity 2 m/s collide head on with another stationary ball of double mass if the coefficient of restitution is 0.5 then their velocities, (m/s ) After collision will be

A ball is moving with a velocity 2 m/s collide head on with another stationary ball of double mass if the coefficient of restitution is 0.5 then their velocities, (m/s ) After collision will be

July 09, 2021 Add Comment KINEMATICS , LAWS OF MOTION , Previous year Questions Edit

[CBSE-PMT-2010]

(a) 0 , 1 (b) 1 , 1 (c) 1 , 0.5 (d) 0 , 2

Let the mass of first ball is 'm' and second (stationary ) ball is '2m'

Coefficient of restitution:

The coefficient of restitution is defined as the ratio of velocity of seperation to the velocity of approch.

i.e.

$coefficient of restitution =\frac{\left ( velocity of seperation \right )}{\left ( velocity of approch \right )}$

$e =\frac{\left ( v_{2} - v_{1} \right )}{\left (u_{2} - u_{1} \right )}$

$0.5 =\frac{v_{2} -v_{1} }{2}$

$v_{2}-v_{1}=0.5*2$

$v_{2}-v_{1}=1$

- - - - ( 1 )

According tothe law of conservation of momentum.

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

Putting the values we get,

$2m+0=mv_1+2mv_2$

$2m =m (v_1+2v_2)$

$v_1+2v_2=2$

- - - - ( 2 )

adding above two equations we get,

$3v_2=3$

$v_2=1{\color{Red} }$

Putting these value in equation (1 ) we get,

$v_2-v_1=1$

$1-v_1=1$

$-v_1=1-1$

$-v_1=0$

$v_1=0$

Their velocities after collision is $v_1=0$ & $v_2=1{\color{Red} }$

Milan Tomic

Hi. I’m Designer of Blog Magic. I’m CEO/Founder of ThemeXpose. I’m Creative Art Director, Web Designer, UI/UX Designer, Interaction Designer, Industrial Designer, Web Developer, Business Enthusiast, StartUp Enthusiast, Speaker, Writer and Photographer. Inspired to make things looks better.

0 comments:

Post a Comment

Subscribe to: Post Comments ( Atom )