In A Guitar, Two Strings A And B Made Of Same Material Are Slightly Out Of Tune And Produce Beats Of Frequency 6 Hz. When Tension In B Is Slightly Decreased, The Beat Frequency Increases To 7 Hz. If The Frequency Of A Is 530 Hz, The Original Frequency Of B Will Be

 [NEET-2020] (a) 523 Hz      (b) 524 Hz      (c) 536 Hz     (d) 537 Hz

THE PHASE DIFFERENCE BETWEEN DISPLACEMENT AND ACCELERATION OF A PARTICLE IN A SIMPLE HARMONIC MOTION IS

 [NEET - 2020] \[(a)\pi rad\] \[(b)\frac{3\pi}{2} rad\] \[(c)\frac{\pi}{2} rad\] \[(d)zero\] Solution: Equation for SHM is