The Ratio Of Emissive Power Of Perfectly Black Body At 1327 Degree C And 527 Degree C Is

(a) 4:1 (b)16:1 (c) 2:1 (d) 8:1

According to Stefan’s Law

The emissive power of a black body is directly proportional to the fourth power of its absolute temperature.

Mathematically,

$R \propto T^4$

Therefore,

$\frac{R_1}{R_2} = \left [\frac{T_1}{T_2} \right ] ^4$

$\frac{R_1}{R_2} = \left [\frac{1327+273}{527+273} \right ] ^4$

$\frac{R_1}{R_2} = \left [\frac{1600}{800} \right ] ^4$

$\frac{R_1}{R_2} = \left [\frac{2}{1} \right ] ^4$

$\frac{R_1}{R_2} = \left [\frac{16}{1} \right ]$

The ratio of emissive power of perfectly black body

$R_1:R_2 = 16:1$

Milan Tomic

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