Home NEET 2020 OSCILLATION Previous year Questions WAVE MOTION In A Guitar, Two Strings A And B Made Of Same Material Are Slightly Out Of Tune And Produce Beats Of Frequency 6 Hz. When Tension In B Is Slightly Decreased, The Beat Frequency Increases To 7 Hz. If The Frequency Of A Is 530 Hz, The Original Frequency Of B Will Be

In A Guitar, Two Strings A And B Made Of Same Material Are Slightly Out Of Tune And Produce Beats Of Frequency 6 Hz. When Tension In B Is Slightly Decreased, The Beat Frequency Increases To 7 Hz. If The Frequency Of A Is 530 Hz, The Original Frequency Of B Will Be

[NEET-2020]

(a) 523 Hz (b) 524 Hz (c) 536 Hz (d) 537 Hz

Let F_A & F_B is the frequency of string A & B respectively.

i.e. either,

$F_A - F_B =6$

- - - - ( 1 )

$F_B - F_A =6$

- - - - ( 2 )

If tension decreases, fB decreases and becomes F_B’

Now, difference of F_A and F_B’ = 7 Hz

i.e. frequency of string ‘A’ is greater than that of string ‘B’. therefore, equation (2) mention above is not possible.

$F_A - F_B =6$

$F_B = F_A -6$

$F_B = 530 -6$

Therefore, the original frequency of B is

$F_B = 524 Hz$

Milan Tomic

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