Home KINEMATICS LAWS OF MOTION NEET 2020 Previous year Questions Two bodies of mass 4 kg and 6 kg are tied to the ends of a massless string. The string passes over a pulley which is frictionless. The acceleration of the system in terms of acceleration due to gravity (g) is :

Two bodies of mass 4 kg and 6 kg are tied to the ends of a massless string. The string passes over a pulley which is frictionless. The acceleration of the system in terms of acceleration due to gravity (g) is :

(a) g (b) g/2 (c) g/5 (d) g/10

Solution

We know that,

Net acceleration acting on system can be given as

$a=\frac{F_{net}}{total\; \; mass}$

$a=\frac{(m_2g)-(m_1g) }{(m_1+m_2)}$

$a=\frac{(m_2-m_1)g }{(m_1+m_2)}$

Putting values we get,

$a=\frac{(6-4)g}{(4+6)}$

$a=\frac{2g}{10}$

Net acceleration acting on system (in terms of 'g') is

$\boldsymbol{\mathbf{\textit{}}{\color{Red} a=\frac{g}{5}}}$

The correct option is option 'C'

Milan Tomic

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