FIND THE TORQUE ABOUT THE ORIGIN WHEN A FORCE OF 3j ̂ N ACTS ON A PARTICLE WHOSE POSITION VECTOR IS 2k ̂ M .

[NEET - 2020] 

\[(a) 6\widehat{i} Nm\]

\[(b) 6\widehat{j} Nm\]
\[(c) -6\widehat{i} Nm\]
\[(d) 6\widehat{k} Nm\]

Solution:
PHYSICS_WITH_AKSHAY_GOLE


\[\overrightarrow{\tau}=\overrightarrow{r}\times \overrightarrow{F}\]
\[\overrightarrow{\tau}=2\widehat{k}\times 3\widehat{j}\]
\[\overrightarrow{\tau}=\begin{vmatrix} \widehat{i} & \widehat{j} &\widehat{k} \\ 0 &0 &2 \\ 0 & 3 &0 \end{vmatrix}\]
\[\overrightarrow{\tau}=\widehat{i}(0-6)+ \widehat{j}(0-0) +\widehat{k}(0-0)\]

THE TORQUE ABOUT THE ORIGIN IS 
\[\overrightarrow{\tau}=-6\widehat{i}\]

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Milan Tomic

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