WHERE,
\[X= \frac{A^{2}B^{\frac{1}{2}}}{C^{\frac{1}{3}D^{3}}}\]
UNIT OF THERMAL CONDUCTIVITY IS [NEET 2019]
a. J m k-1
b. J m-1 k-1
c. W m k-1
d. W m-1 k-1
Solution :
As,
[ % error in X ] = [2 * % error in A]+ [1/2 *% error in B]+ [1/3 *% error in C]+[3 * % error in D]
[ % error in X ] = [2 * 1 % ] + [1/2 * 2% ]+ [1/3 * 3 % ] + [3 * 4 % ]
[ % error in X ] = [ 2 % ] + [ 1% ]+ [ 1% ] + [ 12 % ]
Therefore % error in ‘X’ is
[ % error in X ] = 16%
i.e. option ‘B’ is correct
0 comments:
Post a Comment