WHAT IS THE ANGULAR DISPLACEMENT OF A MINUTE HAND IN 20 MNUTES?

a. 2.095 rad

b. 3.125 rad

c. 1.12 rad

d. 5.421 rad


Solution:


Angular displacement of a body is the angle in radians through which a point revolves around a centre or line has been rotated in a specified sense about a specified axis.

And,

Angular velocity can be defined as the rate of change of angular displacement.

\[ \omega = \frac { \theta } { t } \]

Therefore,

\[\theta=\omega *t\]

\[\theta=\frac{2*\pi }{T} *t\]

( Where, T is time period of minute hand. i.e. time required to complete one revolution= 1hr=60 minutes = 3600 second )

\[\theta=\frac{2*3.14}{3600} *20*60 \]

\[\theta=2.0943 rad\]

 

Therefore, the angular displacement of minute hand in 20 minutes is \[\theta=2.095 rad\]. 

(i.e. option 'a' is correct)

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Milan Tomic

Hi. I’m Designer of Blog Magic. I’m CEO/Founder of ThemeXpose. I’m Creative Art Director, Web Designer, UI/UX Designer, Interaction Designer, Industrial Designer, Web Developer, Business Enthusiast, StartUp Enthusiast, Speaker, Writer and Photographer. Inspired to make things looks better.

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